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Laws of Thermodynamics and Solutions

33 Questions
GATE→2026→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q1
MCQ[1 Mark]
Which one of the following is NOT a state function? (A) Enthalpy (B) Entropy (C) Work (D) Internal Energy
GATE→2026→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q2
MCQ[1 Mark]
For a regular solution, which one of the following statements is correct? (ΔHmix\Delta H_{mix} is the enthalpy of mixing and ΔSmix\Delta S_{mix} is the entropy of mixing) (A) Both ΔHmix\Delta H_{mix} and ΔSmix\Delta S_{mix} are finite (B) ΔHmix\Delta H_{mix} is zero and ΔSmix\Delta S_{mix} is finite (C) ΔHmix\Delta H_{mix} is finite and ΔSmix\Delta S_{mix} is zero (D) Both ΔHmix\Delta H_{mix} and ΔSmix\Delta S_{mix} are zero
GATE→2026→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q3
MSQ[1 Mark]
Choose the correct option(s). Here AA is the Helmholtz free energy and GG is the Gibbs free energy. (A) AA provides a criterion for equilibrium in a system with constant temperature and constant pressure (B) GG provides a criterion for equilibrium in a system with constant temperature and constant pressure (C) AA provides a criterion for equilibrium in a system with constant temperature and constant volume (D) GG provides a criterion for equilibrium in a system with constant temperature and constant volume
GATE→2026→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q4
NAT[1 Mark]
For an equilibrium phase diagram of a binary A-B alloy at a constant pressure as shown in the figure, the degree of freedom at 'X' is (answer in integer)
Figure for Question 4
GATE→2026→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q5
NAT[2 Marks]
20 g20\text{ g} of Au and 20 g20\text{ g} of Ag form an ideal solid solution. Total entropy of mixing is ___ J/K\text{J/K}.
GATE→2026→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q6
NAT[2 Marks]
22 moles of an ideal gas are reversibly expanded from 10 L10\text{ L} to 20 L20\text{ L} isothermally at 27∘C27^\circ\text{C}. Magnitude of work done is ___ Joules.
GATE→2026→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q7
NAT[2 Marks]
For 22 moles of metal with Cp=20+5×10−3TC_p = 20 + 5 \times 10^{-3}T, change in enthalpy upon heating from 300 K300\text{ K} to 600 K600\text{ K} is ___ Joules.
GATE→2026→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q8
NAT[2 Marks]
Given Ellingham oxidation equations for solid and liquid metal M, the melting point of metal M is ___ Kelvin.
GATE→2026→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q9
NAT[2 Marks]
For the combustion of methane with stoichiometric air, estimated adiabatic flame temperature is ___ Kelvin.
GATE→2025→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q10
MCQ[1 Mark]
For an isobaric process, the heat transferred is equal to the change in _______ of the system. (A) enthalpy (B) entropy (C) Helmholtz free energy (D) Gibbs free energy
GATE→2025→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q11
MCQ[1 Mark]
Which one of the following is an intensive property? (A) Chemical potential (B) Volume (C) Mass (D) Entropy
GATE→2025→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q12
MCQ[1 Mark]
Consider the following gas-phase reaction: 2SO2+O2⇌2SO32SO_{2}+O_{2}\rightleftharpoons 2SO_{3}\nIf the enthalpy of reaction is negative, which one of the following conditions promotes a higher equilibrium concentration of SO3SO_{3}? (A) Higher pressure and higher temperature (B) Higher pressure and lower temperature (C) Lower pressure and higher temperature (D) Lower pressure and lower temperature
GATE→2025→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q13
MSQ[1 Mark]
Standard Gibbs free energies of formation of some solid oxides per mole of O2O_2 at 1000 K1000\text{ K} are given below: SiO2SiO_2: −728 kJ-728\text{ kJ}, TiO2TiO_2: −737 kJ-737\text{ kJ}, VOVO: −712 kJ-712\text{ kJ}, MnOMnO: −624 kJ-624\text{ kJ}\nRegarding thermodynamic feasibility of oxide reduction, which of the following statements is/are CORRECT under standard conditions at 1000 K1000\text{ K}? (A) Si can reduce TiO2TiO_2 (B) Mn can reduce VO (C) Ti can reduce MnO (D) V can reduce SiO2SiO_2
GATE→2025→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q14
NAT[1 Mark]
Consider the gas phase reaction: CO+12O2⇌CO2CO + \frac{1}{2}O_2 \rightleftharpoons CO_2\nAt equilibrium for a particular temperature, the partial pressures of COCO, O2O_2, and CO2CO_2 are found to be 10−6 atm10^{-6}\text{ atm}, 10−6 atm10^{-6}\text{ atm}, and 16 atm16\text{ atm}, respectively. The equilibrium constant for the reaction is ___ ×1010\times 10^{10} (rounded off to one decimal place).
GATE→2025→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q15
MCQ[2 Marks]
Consider the phase diagram of a one component system given below. VαV_{\alpha}, VβV_{\beta}, and VLiquidV_{Liquid} are the molar volumes of α\alpha, β\beta, and liquid phases, respectively. Which one of the following statements is TRUE?\nGiven: The change in molar enthalpies, ΔHα→β\Delta H^{\alpha\rightarrow\beta} and ΔHβ→Liquid\Delta H^{\beta\rightarrow Liquid}, are positive. (A) Vα<VβV_{\alpha} < V_{\beta} and Vβ<VLiquidV_{\beta} < V_{Liquid} (B) Vα>VβV_{\alpha} > V_{\beta} and Vβ<VLiquidV_{\beta} < V_{Liquid} (C) Vα<VβV_{\alpha} < V_{\beta} and Vβ>VLiquidV_{\beta} > V_{Liquid} (D) Vα>VβV_{\alpha} > V_{\beta} and Vβ>VLiquidV_{\beta} > V_{Liquid}
Figure for Question 15
GATE→2025→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q16
NAT[2 Marks]
The excess molar Gibbs free energy of a solution of element A and B at 1000 K1000\text{ K} is given by GXS=−3000 XAXB J mol−1G^{XS} = -3000\text{ }X_A X_B\text{ J mol}^{-1}, where XAX_A and XBX_B are mole fractions of A and B, respectively. The activity of B in a solution of A and B containing 40 mol%40\text{ mol}\% of B at 1000 K1000\text{ K} is ___ (rounded off to two decimal places). (Given: R=8.314 J mol−1K−1R = 8.314\text{ J mol}^{-1}\text{K}^{-1})
GATE→2025→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q17
NAT[2 Marks]
Consider the following reactions and their standard Gibbs free energies (in J): Fe(s)+12O2(g)⇌FeO(s)Fe(s) + \frac{1}{2}O_2(g) \rightleftharpoons FeO(s), ΔG∘=−264900+65T\Delta G^\circ = -264900 + 65T 2H2(g)+O2(g)⇌2H2O(g)2H_2(g) + O_2(g) \rightleftharpoons 2H_2O(g), ΔG∘=−492900+109T\Delta G^\circ = -492900 + 109T\nThe value of pH2OpH2\frac{p_{H_2O}}{p_{H_2}} required to reduce solid FeO to solid Fe at 1000 K1000\text{ K} is ___ (rounded off to two decimal places).
GATE→2024→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q18
MCQ[1 Mark]
If in an A-B solid solution, the activity and mole fraction of A are given by aAa_{A} and XAX_{A} respectively, then the activity coefficient of A is given by (A) aAXA\frac{a_{A}}{X_{A}} (B) XAaA\frac{X_{A}}{a_{A}} (C) aAa_{A} (D) aAXA2a_{A}X_{A}^{2}
GATE→2024→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q19
MSQ[1 Mark]
Which of the following is/are criterion/criteria for equilibrium of an isolated system? (A) Maximum entropy (B) Minimum internal energy (C) Minimum Helmholtz free energy (D) Minimization of Gibbs free energy
GATE→2024→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q20
NAT[2 Marks]
An ideal solution is formed by mixing 10 grams10\text{ grams} of A and 50 grams50\text{ grams} of B at 673 K673\text{ K}. The molar free energy of mixing is ___ J mol−1\text{J mol}^{-1} (Round off to one decimal place).\nGiven: Universal gas constant R=8.314 J mol−1K−1R = 8.314\text{ J mol}^{-1}\text{K}^{-1}, atomic weight of A=40 g mol−1\text{A} = 40\text{ g mol}^{-1}, atomic weight of B=60 g mol−1\text{B} = 60\text{ g mol}^{-1}
GATE→2024→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q21
NAT[2 Marks]
800 grams of A-B alloy containing 20 wt.%20\text{ wt.}\% B is held at temperature T1T_1. The weight of B dissolved in α\alpha at that temperature is ___ grams (Round off to the nearest integer).
Figure for Question 21
GATE→2023→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q22
MCQ[1 Mark]
At one atmosphere pressure, α\alpha-Fe transforms to γ\gamma-Fe above 912∘C912^{\circ}\text{C}. Density of γ\gamma-Fe is more than that of α\alpha-Fe. Choose the correct statement. (A) Increasing the pressure above one atmosphere lowers the α\alpha-Fe to γ\gamma-Fe transformation temperature. (B) Increasing the pressure above one atmosphere raises the α\alpha-Fe to γ\gamma-Fe transformation temperature. (C) Molar volume of γ\gamma-Fe is higher than the molar volume of α\alpha-Fe. (D) Pressure change will not have any effect on the α\alpha-Fe to γ\gamma-Fe transformation temperature.
GATE→2023→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q23
MCQ[1 Mark]
Formation of an ideal solution leads to (A) increase in entropy (B) decrease in volume (C) increase in enthalpy (D) decrease in entropy
GATE→2023→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q24
MCQ[1 Mark]
At one atmosphere pressure, iron (Fe) and nickel (Ni) oxidize as: 2Fe+O2↔2FeO2Fe + O_{2} \leftrightarrow 2FeO, ΔG∘=−527400+128T Joules\Delta G^{\circ} = -527400 + 128T\text{ Joules} 2Ni+O2↔2NiO2Ni + O_{2} \leftrightarrow 2NiO, ΔG∘=−471200+172T Joules\Delta G^{\circ} = -471200 + 172T\text{ Joules}\nIdentify the correct statement. Given: Temperature TT is in Kelvin. (A) Fe can reduce NiO at all temperatures (B) Fe can reduce NiO only above 1000 K (C) Ni can reduce FeO at all temperatures (D) Ni can reduce FeO only above 1000 K
GATE→2023→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q25
NAT[1 Mark]
Maximum number of phases that can be in equilibrium for a 5-component system at constant temperature and pressure is ___ (in integer).
GATE→2023→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q26
MCQ[2 Marks]
Taking SS as entropy, TT as temperature, PP as pressure, and VV as volume, match Column I with Column II.\nColumn I: (A) Gibbs Free Energy (B) Helmholtz Free Energy (C) Enthalpy (D) Internal Energy\nColumn II: (1) depends on T,VT, V and composition (2) depends on T,PT, P and composition (3) depends on S,PS, P and composition (4) depends on S,VS, V and composition (A) A-2, B-1, C-3, D-4 (B) A-4, B-3, C-2, D-1 (C) A-3, B-1, C-4, D-2 (D) A-2, B-1, C-4, D-3
GATE→2023→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q27
MSQ[2 Marks]
Concerning the chemical potentials of components in a binary system at constant pressure, the correct statement(s) is/are (A) For single-phase equilibrium at a given temperature, chemical potentials of the components change with alloy composition. (B) For two-phase equilibrium at a given temperature, chemical potential of any component in both phases is same. (C) For two-phase equilibrium at a given temperature, chemical potentials of the components change with alloy composition. (D) For single-phase equilibrium of a given composition, chemical potentials of the components do not change with temperature.
GATE→2023→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q28
NAT[2 Marks]
Enthalpy of formation of an A-B regular solution containing 80 atomic percent A80\text{ atomic percent A} is 3.36 kJ mol−13.36\text{ kJ mol}^{-1}. The activity coefficient of A at 500 K500\text{ K} for the solution containing 40 atomic percent A40\text{ atomic percent A} is ___ (round off to 1 decimal place).\nGiven: Universal gas constant, R=8.314 J mol−1K−1R = 8.314\text{ J mol}^{-1}\text{K}^{-1}
GATE→2023→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q29
NAT[2 Marks]
The alloy A (given in the phase diagram) is cooled slowly from the liquid state to just below the eutectic temperature. The ratio of weight fractions of pro-eutectic α\alpha to eutectic α\alpha is ___ (round off to 1 decimal place).
Figure for Question 29
GATE→2022→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q30
NAT[2 Marks]
What is the equilibrium pCOpCO2\frac{p_{CO}}{p_{CO_{2}}} ratio for the given reaction at 1873 K1873\text{ K}? (round off to 2 decimal places) Mo(s)+O2(g)↔MoO2(s)Mo(s) + O_{2}(g) \leftrightarrow MoO_{2}(s)\nGiven: ΔfG1873∘=−262300 J\Delta_{f}G^{\circ}_{1873} = -262300\text{ J}; aMoO2(s)=0.5a_{MoO_{2}(s)} = 0.5 and ΔrG1873∘=−120860 J\Delta_{r}G^{\circ}_{1873} = -120860\text{ J} for the reaction CO(g)+0.5O2(g)↔CO2(g)CO(g) + 0.5O_{2}(g) \leftrightarrow CO_{2}(g); R=8.314 J K−1mol−1R = 8.314\text{ J K}^{-1}\text{mol}^{-1}.
GATE→2022→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q31
NAT[2 Marks]
The partial molar enthalpy of Au in Ag-Au melt containing 25 mol%25\text{ mol}\% Au at 1400 K1400\text{ K} is −8300 J⋅mol−1-8300\text{ J}\cdot\text{mol}^{-1}. Assuming regular solution behavior, the activity of Au in the melt is ___ (round off to 3 decimal places).\nGiven: R=8.314 J⋅K−1⋅mol−1R = 8.314\text{ J}\cdot\text{K}^{-1}\cdot\text{mol}^{-1}
GATE→2022→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q32
NAT[2 Marks]
Assuming that Dulong-Petit law is valid for a monoatomic solid, the ratio of heat capacities CpCv\frac{C_p}{C_v} at 500 K500\text{ K} is ___ (round off to 3 decimals).\nGiven: molar volume =7×10−6 m3⋅mol−1= 7 \times 10^{-6}\text{ m}^3\cdot\text{mol}^{-1}, isothermal compressibility β=8×10−12 Pa−1\beta = 8 \times 10^{-12}\text{ Pa}^{-1}, isobaric expansivity α=6×10−5 K−1\alpha = 6 \times 10^{-5}\text{ K}^{-1}, and R=8.314 J⋅K−1⋅mol−1R = 8.314\text{ J}\cdot\text{K}^{-1}\cdot\text{mol}^{-1}.
GATE→2022→Metallurgical Thermodynamics→Laws of Thermodynamics and Solutions
Q33
NAT[2 Marks]
The equilibrium microstructure of an alloy A-B consists of two phases α\alpha and β\beta in the molar proportion 2:12:1. If the overall composition of the alloy is 70 mol%70\text{ mol}\% B and the composition of β\beta is 90 mol%90\text{ mol}\% B, the composition of α\alpha is ___ (in mol% B) (round off to the nearest integer).

Electrochemistry

4 Questions
GATE→2025→Metallurgical Thermodynamics→Electrochemistry
Q34
NAT[2 Marks]
Consider the following cell reaction: Mg+Cd2+⇌Mg2++CdMg + Cd^{2+} \rightleftharpoons Mg^{2+} + Cd\nThe standard Gibbs free energy change for the reaction is ___ kJ\text{kJ} (rounded off to an integer).\nGiven: Standard oxidation potentials are Mg⇌Mg2++2e−Mg \rightleftharpoons Mg^{2+} + 2e^-, E∘=2.37 VE^\circ = 2.37\text{ V}; Cd⇌Cd2++2e−Cd \rightleftharpoons Cd^{2+} + 2e^-, E∘=0.403 VE^\circ = 0.403\text{ V}. Faraday's constant =96500 C mol−1= 96500\text{ C mol}^{-1}
GATE→2024→Metallurgical Thermodynamics→Electrochemistry
Q35
NAT[2 Marks]
The cupric ion (Cu2+Cu^{2+}) concentration in the electrolyte (at 298 K298\text{ K}) required to make the potential of pure copper equal to 0.17 V0.17\text{ V} is ___ ×10−6 gram-mol (litre)−1\times 10^{-6}\text{ gram-mol (litre)}^{-1} (Round off to two decimal places). (Given: R=8.314 J mol−1K−1R = 8.314\text{ J mol}^{-1}\text{K}^{-1}, F=96500 C mol−1F = 96500\text{ C mol}^{-1}, standard reduction potential E∘=0.34 VE^\circ = 0.34\text{ V})
GATE→2023→Metallurgical Thermodynamics→Electrochemistry
Q36
NAT[2 Marks]
In an aqueous solution of Fe2+Fe^{2+} ions with concentration of 10−4 M10^{-4}\text{ M} at 298 K298\text{ K} and atmospheric pressure, the reduction potential of Fe in volt is ___ (round off to 2 decimal places).\nGiven: Standard reduction potential, EFe2+/Fe∘=−0.44 VE^{\circ}_{Fe^{2+}/Fe} = -0.44\text{ V}, Faraday's constant F=96500 C mol−1F = 96500\text{ C mol}^{-1}, Universal gas constant R=8.314 J mol−1K−1R = 8.314\text{ J mol}^{-1}\text{K}^{-1}
GATE→2022→Metallurgical Thermodynamics→Electrochemistry
Q37
NAT[2 Marks]
The emf of the cell Au-Pb(liquid) ∣ PbCl2-KCl(liquid) ∣ Cl2(gas, 0.5 atm), C(graphite)\text{Au-Pb(liquid) } | \text{ PbCl}_2\text{-KCl(liquid) } | \text{ Cl}_2\text{(gas, } 0.5\text{ atm), C(graphite)}\nis 1.2327 V1.2327\text{ V} at 873 K873\text{ K}. Activity of Pb in the Au-Pb alloy is 0.720.72 and the activity of PbCl2\text{PbCl}_2 in the electrolyte is 0.180.18. The standard Gibbs energy of formation of PbCl2(liquid)\text{PbCl}_2\text{(liquid)} at 873 K873\text{ K} is ___ kJ⋅mol−1\text{kJ}\cdot\text{mol}^{-1} (round off to 1 decimal place).\nGiven: R=8.314 J⋅K−1⋅mol−1R = 8.314\text{ J}\cdot\text{K}^{-1}\cdot\text{mol}^{-1} and F=96500 C⋅mol−1F = 96500\text{ C}\cdot\text{mol}^{-1}.